Seconsett Island, Massachusetts

Seconsett Island is a census-designated place (CDP) in the town of Mashpee in Barnstable County, Massachusetts, United States. The population was 100 at the 2010 census.GeographySeconsett Island is located in the southwest part of the town of Mashpee at . It is bounded by the town of Falmouth to the northwest, by Hamblin Pond to the northeast, by the Little River to the southeast, and by Waquoit Bay to the southwest. The only road access is via Meadow Neck Road from Falmouth.According to the United States Census Bureau, the CDP has a total area of 0.28sqkm, of which 0.01sqkm, or 4.53%, is water.DemographicsAs of the census of 2000, there were 81 people, 43 households, and 23 families residing in the CDP. The population density was 284.3/km² (749.7/mi²). There were 141 housing units at an average density of 494.9/km² (1,305.0/mi²). The racial makeup of the CDP was 100.00% White.There were 43 households out of which 9.3% had children under the age of 18 living with them, 39.5% were married couples living together, 9.3% had a female householder with no husband present, and 46.5% were non-families. 34.9% of all households were made up of individuals and 25.6% had someone living alone who was 65 years of age or older. The average household size was 1.88 and the average family size was 2.39.